Proof 2 of Pythagoras’ Theorem

Here’s a second proof of the legendary Pythagoras’ Theorem:

In this diagram:

• There is a large square, with length C
• There is a small square, with length B – A, inside the large square.

It follows that the area of the large square = C^2.

C^2 = 4 (1/2 x A x B) + (B – A)^2

This is the area of the small square added to the areas of the four right-angled triangles.

When simplified:

C^2 = 2AB + B^2 – 2AB + A^2

C^2 = B^2 + A^2

QED